"""
验证 ts_rank 和除法 Bug 修复的测试
"""

import polars as pl
import numpy as np
from src.factors import FactorEngine


def test_ts_rank_nan_handling():
    """测试 ts_rank 正确处理 NaN 值，不应该将 NaN 转换为 0.0"""
    print("=" * 60)
    print("测试 ts_rank NaN 处理")
    print("=" * 60)

    # 创建包含 NaN 的测试数据
    df = pl.DataFrame(
        {
            "trade_date": ["20240101", "20240101", "20240101", "20240101", "20240101"]
            * 2,
            "ts_code": ["000001.SZ"] * 5 + ["000002.SZ"] * 5,
            "close": [
                1.0,
                2.0,
                np.nan,
                4.0,
                5.0,  # 股票1：第3个是NaN
                2.0,
                3.0,
                4.0,
                5.0,
                6.0,
            ],  # 股票2：正常数据
        }
    )

    print("输入数据:")
    print(df)

    # 使用引擎计算 ts_rank
    engine = FactorEngine()
    # 手动设置数据（这里用简单方式）

    # 直接测试 translator
    from src.factors.translator import PolarsTranslator
    from src.factors.parser import FormulaParser
    from src.factors.registry import FunctionRegistry

    parser = FormulaParser(FunctionRegistry())
    ast = parser.parse("ts_rank(close, 3)")

    translator = PolarsTranslator()
    expr = translator.translate(ast)

    result = df.with_columns([expr.alias("ts_rank_result")])

    print("\nts_rank 结果:")
    print(result.select(["trade_date", "ts_code", "close", "ts_rank_result"]))

    # 验证：NaN 输入应该产生 NaN 输出，而不是 0.0
    stock1_data = result.filter(pl.col("ts_code") == "000001.SZ")
    nan_input_row = stock1_data.filter(pl.col("close").is_nan())

    if nan_input_row.height > 0:
        rank_value = nan_input_row["ts_rank_result"][0]
        if np.isnan(rank_value):
            print("\n[PASS] NaN 输入正确产生了 NaN 输出")
            return True
        elif rank_value == 0.0:
            print(f"\n[FAIL] NaN 输入被错误转换为 0.0！")
            return False
        else:
            print(f"\n[FAIL] 意外的输出值: {rank_value}")
            return False
    else:
        print("\n[SKIP] 没有找到 NaN 输入行")
        return False


def test_division_by_zero():
    """测试除法处理除零情况，不应该产生 NaN/inf"""
    print("\n" + "=" * 60)
    print("测试除法除零处理")
    print("=" * 60)

    # 创建包含零的数据
    df = pl.DataFrame(
        {
            "trade_date": ["20240101", "20240101", "20240101"],
            "ts_code": ["000001.SZ", "000002.SZ", "000003.SZ"],
            "numerator": [100.0, 100.0, 100.0],
            "denominator": [10.0, 0.0, 5.0],  # 中间那个是0
        }
    )

    print("输入数据:")
    print(df)

    # 直接测试 translator
    from src.factors.translator import PolarsTranslator
    from src.factors.parser import FormulaParser
    from src.factors.registry import FunctionRegistry

    parser = FormulaParser(FunctionRegistry())
    ast = parser.parse("numerator / denominator")

    translator = PolarsTranslator()
    expr = translator.translate(ast)

    result = df.with_columns([expr.alias("division_result")])

    print("\n除法结果:")
    print(result.select(["ts_code", "numerator", "denominator", "division_result"]))

    # 验证：除零应该产生 Null，而不是 NaN/inf
    zero_row = result.filter(pl.col("denominator") == 0.0)
    if zero_row.height > 0:
        div_value = zero_row["division_result"][0]
        if div_value is None:
            print("\n[PASS] 除零正确产生了 Null")
            return True
        elif np.isnan(div_value) or np.isinf(div_value):
            print(f"\n[FAIL] 除零产生了 NaN/inf: {div_value}")
            return False
        else:
            print(f"\n[?] 除零产生了: {div_value} (可能是其他有效值)")
            return True  # 也可能是预期的行为
    else:
        print("\n[SKIP] 没有找到除零行")
        return False


if __name__ == "__main__":
    test1_pass = test_ts_rank_nan_handling()
    test2_pass = test_division_by_zero()

    print("\n" + "=" * 60)
    print("测试结果汇总")
    print("=" * 60)
    print(f"ts_rank NaN 处理: {'PASS' if test1_pass else 'FAIL'}")
    print(f"除法除零处理: {'PASS' if test2_pass else 'FAIL'}")

    if test1_pass and test2_pass:
        print("\n所有测试通过！")
    else:
        print("\n部分测试失败，请检查实现")