fix(data): 修复财务因子计算非确定性问题
重构 financial_loader 的去重逻辑,确保截面排名计算的股票集合一致: - 引入"高水位线"算法剔除陈旧历史财报(解决2026年发布2021年财报的问题) - 改变去重策略:按报告期(end_date)而非更新标识(update_flag)保留最新数据 - 扩展回看期从1年到2年,防止ST/停牌公司财报缺失 - 确保相同交易日在不同查询范围下返回一致的财务数据
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@@ -16,7 +16,7 @@ def create_mock_price_data() -> pl.DataFrame:
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"""创建模拟行情数据。"""
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return pl.DataFrame(
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{
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"ts_code": ["000001.SZ"] * 10,
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"ts_code": ["000001.SZ"] * 12,
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"trade_date": [
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"20240101",
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"20240102",
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@@ -28,8 +28,24 @@ def create_mock_price_data() -> pl.DataFrame:
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"20240110",
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"20240111",
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"20240112",
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# 添加2024-04-30之后的日期,用于测试同日不同报告期场景
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"20240501",
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"20240502",
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],
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"close": [
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10.0,
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10.2,
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10.3,
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10.1,
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10.5,
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10.6,
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10.4,
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10.7,
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10.8,
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10.9,
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11.0,
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11.1,
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],
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"close": [10.0, 10.2, 10.3, 10.1, 10.5, 10.6, 10.4, 10.7, 10.8, 10.9],
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}
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)
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@@ -37,31 +53,63 @@ def create_mock_price_data() -> pl.DataFrame:
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def create_mock_financial_data() -> pl.DataFrame:
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"""创建模拟财务数据(覆盖多种场景)。
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场景说明:
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1. 2024-01-02 发布 2023Q3 报告(end_date=20230930)
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2. 2024-01-02 发布 2023Q3 更正版(update_flag=1)
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3. 2024-04-30 同时发布 2023年报(end_date=20231231)和 2024Q1季报(end_date=20240331)
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4. 2024-04-30 发布 2023年报更正版
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预期结果:
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- 2024-01-02 保留 2023Q3 更正版
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- 2024-04-30 保留 2024Q1 季报(end_date 最新)
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注意:f_ann_date 必须是 Date 类型(与数据库保持一致)。
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"""
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return pl.DataFrame(
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{
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"ts_code": ["000001.SZ", "000001.SZ", "000001.SZ", "000001.SZ"],
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# 场景1: 2023Q3 报告,正常公告
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# 场景2: 同日多版(update_flag 区分)
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# 场景3: 隔日修改
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"ts_code": [
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"000001.SZ",
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"000001.SZ",
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"000001.SZ",
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"000001.SZ",
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"000001.SZ",
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],
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"f_ann_date": [
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date(2024, 1, 2),
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date(2024, 1, 2),
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date(2024, 1, 5),
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date(2024, 1, 10),
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date(2024, 1, 2), # 同日多版
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date(2024, 4, 30),
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date(2024, 4, 30),
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date(2024, 4, 30), # 同日不同报告期
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],
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"end_date": [
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"20230930",
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"20230930", # 2023Q3
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"20231231",
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"20240331",
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"20231231", # 年报和季报同一天发布
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],
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"report_type": [1, 1, 1, 1, 1], # 整数类型(与数据库一致)
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"update_flag": [0, 1, 0, 0, 1], # 年报也有更正版
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"net_profit": [
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1000000.0,
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1100000.0, # 2023Q3
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5000000.0,
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1500000.0,
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5500000.0, # 年报更正后550万,季报150万
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],
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"revenue": [
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5000000.0,
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5200000.0, # 2023Q3
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20000000.0,
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8000000.0,
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22000000.0,
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],
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"end_date": ["20230930", "20230930", "20230930", "20231231"],
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"report_type": [1, 1, 1, 1], # 整数类型(与数据库一致)
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"update_flag": [0, 1, 1, 1], # 整数类型(与数据库一致)
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"net_profit": [1000000.0, 1100000.0, 1100000.0, 1200000.0],
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"revenue": [5000000.0, 5200000.0, 5200000.0, 6000000.0],
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}
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)
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def test_financial_data_cleaning():
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"""测试财务数据清洗逻辑。"""
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"""测试财务数据清洗逻辑 - 确保同日多报告期时选 end_date 最新的。"""
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print("=== 测试 1: 财务数据清洗 ===")
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df_finance = create_mock_financial_data()
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@@ -70,36 +118,61 @@ def test_financial_data_cleaning():
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loader = FinancialLoader()
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# 手动执行清洗(模拟 load_financial_data 的逻辑)
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# 步骤1: 仅保留合并报表
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# 手动执行新的清洗逻辑
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df = df_finance.filter(pl.col("report_type") == 1)
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# 步骤2: 按 update_flag 降序排列后去重
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# 添加辅助列
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df = df.with_columns(
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[pl.col("update_flag").cast(pl.Int32).alias("update_flag_int")]
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[
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pl.col("end_date").cast(pl.Int32).alias("end_date_int"),
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pl.col("update_flag")
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.fill_null("0")
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.cast(pl.Int32, strict=False)
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.fill_null(0)
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.alias("update_flag_int"),
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]
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)
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df = df.sort(
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["ts_code", "f_ann_date", "update_flag_int"], descending=[False, False, True]
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# 确定性排序
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df = df.sort(["ts_code", "f_ann_date", "end_date_int", "update_flag_int"])
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# 累积最大报告期
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df = df.with_columns(
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pl.col("end_date_int").cum_max().over("ts_code").alias("max_end_date_seen")
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)
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df = df.unique(subset=["ts_code", "f_ann_date"], keep="first")
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df = df.drop("update_flag_int")
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# 过滤历史包袱
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df = df.filter(pl.col("end_date_int") == pl.col("max_end_date_seen"))
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# 步骤3: 排序(f_ann_date 已经是 Date 类型)
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# 去重保留最后一条(end_date 最大的)
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df = df.unique(subset=["ts_code", "f_ann_date"], keep="last")
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# 清理辅助列
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df = df.drop(["end_date_int", "update_flag_int", "max_end_date_seen"])
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df = df.sort(["ts_code", "f_ann_date"])
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print("\n清洗后的财务数据:")
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print(df)
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# 验证:应该有3条记录(第1-2行去重为1条,第3行,第4行)
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assert len(df) == 3, f"清洗后应该有3条记录,实际有 {len(df)} 条"
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# 验证:应该有2条记录(2024-01-02 和 2024-04-30)
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assert len(df) == 2, f"清洗后应该有2条记录,实际有 {len(df)} 条"
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# 验证:2024-01-02 的 update_flag 应该是 1
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# 验证:2024-01-02 的 end_date 应该是 20230930
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row_jan02 = df.filter(pl.col("f_ann_date") == date(2024, 1, 2))
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assert len(row_jan02) == 1, "应该有1条 2024-01-02 的记录"
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assert row_jan02["update_flag"][0] == 1, "update_flag 应该为 1"
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assert row_jan02["net_profit"][0] == 1100000.0, "net_profit 应该为 1100000"
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assert len(row_jan02) == 1
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assert row_jan02["end_date"][0] == "20230930"
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assert row_jan02["update_flag"][0] == 1
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print("[验证 1] 2024-01-02 正确保留了 2023Q3 更正版")
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# 验证:2024-04-30 应该保留 2024Q1(end_date=20240331),而不是年报
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row_apr30 = df.filter(pl.col("f_ann_date") == date(2024, 4, 30))
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assert len(row_apr30) == 1
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assert row_apr30["end_date"][0] == "20240331", (
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f"2024-04-30 应该保留 end_date 最新的 20240331,"
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f"实际为 {row_apr30['end_date'][0]}"
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)
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assert row_apr30["net_profit"][0] == 1500000.0
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print("[验证 2] 2024-04-30 正确保留了 2024Q1 季报(end_date 最新)")
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print("\n[通过] 财务数据清洗测试通过!")
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return df
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@@ -114,17 +187,44 @@ def test_financial_price_merge():
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loader = FinancialLoader()
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# 步骤1: 清洗财务数据(手动执行)
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# 步骤1: 清洗财务数据(手动执行新的清洗逻辑)
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# 注意:f_ann_date 已经是 Date 类型,不需要转换
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df_finance = df_finance_raw.filter(pl.col("report_type") == 1)
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# 添加辅助列
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df_finance = df_finance.with_columns(
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[pl.col("update_flag").cast(pl.Int32).alias("update_flag_int")]
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[
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pl.col("end_date").cast(pl.Int32).alias("end_date_int"),
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pl.col("update_flag")
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.fill_null("0")
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.cast(pl.Int32, strict=False)
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.fill_null(0)
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.alias("update_flag_int"),
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]
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)
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# 确定性排序
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df_finance = df_finance.sort(
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["ts_code", "f_ann_date", "update_flag_int"], descending=[False, False, True]
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["ts_code", "f_ann_date", "end_date_int", "update_flag_int"]
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)
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# 累积最大报告期
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df_finance = df_finance.with_columns(
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pl.col("end_date_int").cum_max().over("ts_code").alias("max_end_date_seen")
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)
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# 过滤历史包袱
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df_finance = df_finance.filter(
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pl.col("end_date_int") == pl.col("max_end_date_seen")
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)
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# 去重保留最后一条(end_date 最大的)
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df_finance = df_finance.unique(subset=["ts_code", "f_ann_date"], keep="last")
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# 清理辅助列
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df_finance = df_finance.drop(
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["end_date_int", "update_flag_int", "max_end_date_seen"]
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)
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df_finance = df_finance.unique(subset=["ts_code", "f_ann_date"], keep="first")
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df_finance = df_finance.drop("update_flag_int")
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df_finance = df_finance.sort(["ts_code", "f_ann_date"])
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print("清洗后的财务数据:")
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@@ -166,15 +266,22 @@ def test_financial_price_merge():
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assert jan04["net_profit"][0] == 1100000.0, "2024-01-04 应延续使用 2023Q3 数据"
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print("[验证 3] 2024-01-04 net_profit=1100000 - 正确(延续使用)")
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# 20240110 应切换到 2023Q4 数据(新公告)
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# 20240110 应延续使用 2023Q3 数据(2024-04-30 还未公告)
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jan10 = merged.filter(pl.col("trade_date") == "20240110")
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assert jan10["net_profit"][0] == 1200000.0, "2024-01-10 应切换到 2023Q4 数据"
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print("[验证 4] 2024-01-10 net_profit=1200000 - 正确(新财报公告)")
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assert jan10["net_profit"][0] == 1100000.0, "2024-01-10 应延续使用 2023Q3 数据"
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print("[验证 4] 2024-01-10 net_profit=1100000 - 正确(延续使用 2023Q3)")
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# 20240112 应继续延续使用 2023Q4 数据
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# 20240112 应继续延续使用 2023Q3 数据
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jan12 = merged.filter(pl.col("trade_date") == "20240112")
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assert jan12["net_profit"][0] == 1200000.0, "2024-01-12 应继续使用 2023Q4 数据"
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print("[验证 5] 2024-01-12 net_profit=1200000 - 正确(延续使用)")
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assert jan12["net_profit"][0] == 1100000.0, "2024-01-12 应继续使用 2023Q3 数据"
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print("[验证 5] 2024-01-12 net_profit=1100000 - 正确(延续使用 2023Q3)")
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# 20240501 应切换到 2024Q1 数据(2024-04-30 已公告,且选择 end_date 最新的)
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may01 = merged.filter(pl.col("trade_date") == "20240501")
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assert may01["net_profit"][0] == 1500000.0, "2024-05-01 应切换到 2024Q1 数据"
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print(
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"[验证 6] 2024-05-01 net_profit=1500000 - 正确(切换到 2024Q1,end_date 最新)"
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)
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print("\n[通过] 所有验证通过,无未来函数!")
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return merged
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